Quantum Computing (Pragmatic Bookshelf)
Latest Threads About This Book
.When leaving |1> alone, the second column should be (0 1) (i.e. c=0, d=1), not the other way around.
Likewise when leaving |0> al...
New
Here the term Hermtian matrix is misused as synonymous to conjugate transpose (of a given matrix). In fact, a Hermitian (or self-adjoint)...
New
the statement “The quantum state of a qubit is obtained by reading across a row … |0011>” seems quite problematic to me.
First, the q...
New
Title: Quantum Computing: The angle of rotation of the 0 qubelets and 1 qubelets are inconsistent across several pages (pages 400, 402, ...
New
@nihal.mehta
Title: Quantum Computing: Angle referred to with \theta symbol instead of \alpha symbol (page 402)
Example: Quantum Comput...
New
@nihal.mehta
Stated: The NOT (X) gate is equivalent to the U3(pi, pi, 0, ) gate.
I tried that in the U3 matrix, but I got a different r...
New
(a+ib)^2 = a^2 + 2iab - b^2, not a^2 + 2iab + b^2.
In the next line, c = a^2 - b^2, not a^2 + b^2.
New
Stated: “The S gate then rotates the triangle |1> qubelet 90 degrees, or a quarter turn clockwise”. The figure turns it anticlockwise....
New
It states the two matrices being multiplied are A(Z) and A(CNOT). They should be A(CZ) and A(CNOT). The next line where the matrices are ...
New
@nihal.mehta
“The top six cells in each qubelet column are identical to those shown in” should be “the top seven cells…”. q[0] to q[6] i...
New
@nihal.mehta
I’m just starting with quantum computing, therefore I’m not completely sure. But for me the bottom-left X gate in the circu...
New
On page 187 in section “Can the Quantum Gate Matrix Be Anything?”, psi-dagger is defined as <psi^dagger| = (w0* w1*).
As per my under...
New
Given a qubit with 3 pentagon |0> qubelets and 1 triangle |1> qubelet. As described on p. 40 and in the answer to question 1.b.ii, ...
New
At the end of page 65, ‘The target is the qubit in the q[5] register’, it should be the q[4] register.
New
Quantum computing overhauls computer science. Designing life-saving drugs and solving super-large logistics problems that are difficult o...
New
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the statement “The quantum state of a qubit is obtained by reading across a row … |0011>” seems quite problematic to me.
First, the q...
New
@nihal.mehta
“The top six cells in each qubelet column are identical to those shown in” should be “the top seven cells…”. q[0] to q[6] i...
New
@nihal.mehta
Stated: The NOT (X) gate is equivalent to the U3(pi, pi, 0, ) gate.
I tried that in the U3 matrix, but I got a different r...
New
Title: Quantum Computing: The angle of rotation of the 0 qubelets and 1 qubelets are inconsistent across several pages (pages 400, 402, ...
New
(a+ib)^2 = a^2 + 2iab - b^2, not a^2 + 2iab + b^2.
In the next line, c = a^2 - b^2, not a^2 + b^2.
New
It states the two matrices being multiplied are A(Z) and A(CNOT). They should be A(CZ) and A(CNOT). The next line where the matrices are ...
New
@nihal.mehta
Title: Quantum Computing: Angle referred to with \theta symbol instead of \alpha symbol (page 402)
Example: Quantum Comput...
New
Stated: “The S gate then rotates the triangle |1> qubelet 90 degrees, or a quarter turn clockwise”. The figure turns it anticlockwise....
New
Here the term Hermtian matrix is misused as synonymous to conjugate transpose (of a given matrix). In fact, a Hermitian (or self-adjoint)...
New
.When leaving |1> alone, the second column should be (0 1) (i.e. c=0, d=1), not the other way around.
Likewise when leaving |0> al...
New
Most Active Over Three Years
Quantum computing overhauls computer science. Designing life-saving drugs and solving super-large logistics problems that are difficult o...
New
Given a qubit with 3 pentagon |0> qubelets and 1 triangle |1> qubelet. As described on p. 40 and in the answer to question 1.b.ii, ...
New
On page 187 in section “Can the Quantum Gate Matrix Be Anything?”, psi-dagger is defined as <psi^dagger| = (w0* w1*).
As per my under...
New
At the end of page 65, ‘The target is the qubit in the q[5] register’, it should be the q[4] register.
New
@nihal.mehta
I’m just starting with quantum computing, therefore I’m not completely sure. But for me the bottom-left X gate in the circu...
New
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